Question: How do you incorporate the Oracle UPPER function with the Oracle LIKE condition? I'm trying to query against a free text field for all records containing the word "test". For example, it would return a value such as 'Hello_'. This Oracle LIKE condition example returns all suppliers whose name starts with H and ends in _. WHERE supplier_name LIKE 'H%!_' ESCAPE '!' You can also use the escape character with the _ character in the Oracle LIKE condition. For example, it would return a value such as 'Hello%'. This Oracle LIKE condition example returns all suppliers whose name starts with H and ends in %. WHERE supplier_name LIKE 'H%!%' ESCAPE '!' Here is another more complicated example using escape characters in the Oracle LIKE condition. This statement will return all suppliers whose name is Water%. This Oracle LIKE condition example identifies the ! character as an escape character. WHERE supplier_name LIKE 'Water!%' ESCAPE '!' Please note that you can only define an escape character as a single character (length of 1). You can do this using an Escape character. Let's say you wanted to search for a % or a _ character in the Oracle LIKE condition. These examples deal specifically with escaping characters in Oracle.
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It is important to understand how to "Escape Characters" when pattern matching. The example above, would retrieve potentially 10 records back (where the missing value could equal anything from 0 to 9). You might find that you are looking for an account number, but you only have 5 of the 6 digits. For example, it could return suppliers whose supplier_name is 'Smith', 'Smyth', 'Smath', 'Smeth', etc.
This Oracle LIKE condition example would return all suppliers whose supplier_name is 5 characters long, where the first two characters is 'Sm' and the last two characters is 'th'. Remember that _ wildcard is looking for only one character. Next, let's explain how the _ wildcard (underscore wildcard) works in the Oracle LIKE condition. Example - Using _ wildcard (underscore wildcard)
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